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A block of mass 2kg lying on ice when gi...

A block of mass 2kg lying on ice when given a velocity of `6ms^(-1)` is stopped by friction in 5s. The coefficient of friction between the block and ice is (g=10 `ms^(-2)`)

A

0.5

B

0.2

C

0.12

D

0.4

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • A marble block of mass 2 kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 10s. Then the coefficient of friction is (g = 10 ms^(-2) )

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    0.02
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    C
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    D
    0.01

  • A marble block of mass 2 kg lying on ice when given a velocity of 6 ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g = 10 ms^(-2))

    A
    0.02
    B
    0.03
    C
    0.06
    D
    0.01

  • A marble block of mass 2 kg lying on ice when given a velocity of 6 ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g=10 ms^(-2))

    A
    `0.02`
    B
    `0.03`
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