A particle traversed half of the distance with a velocity of `V_(0)`.The remaining parts of the distance was covered with velocity `V_(1)`, for half of the time and with `V_(2)` for other half of the time .Find the mean velocity of the particle averahed and the whole time of motion .

Answer

2

Explanation

Average velocity for the second half distance=
`(v_(1)(t)/(2)+v_(2)(t)/(2))/((t)/(2)+(t)/(2))=(v_(1)+v_(2))/(2)`
Average for the first hald distance ==`v_(0)`
(`therefore` it is constant)
Average velocity for total path