A body starts from rest and moves with uniform acceleration of `5ms^(-2)` for 8 seconds.From that time the acceleration ceases.Find the distance covered in 12s starting from rest.

Explanation

The velocity after 8 seconds
v=0+`5xx8`=40 m/s
Distance covered in 8 seconds
`S_(0)=0+(1)/(2)xx5xx64=160m`
After 8s the body with uniform velocity and distance covered in 4s with uniform velocity is
S=vt=`40xx4`=160 m
The distance covered in
12s =160+160=320 m.