Home
Class 12
PHYSICS
A car starts from rest and moves with un...

A car starts from rest and moves with uniform acceleration 'a' .At the same point a bike crosses with a uniform velocity 'u'.
When and where will they meet ?What is the velocity of car with respect to the bike at the time of meeting?

Text Solution

Verified by Experts

Let the car and bike will meet after covering a distance S in a time .t. sec.
For car S`(1)/(2)at^(2)`………..(1)
For bike S=ut……….(2)
Since they cover same distance
`ut=(1)/(2)at^(2)impliest=(2u)/(u)`
The car and bike will meet after a time of `(2u)/(a)` sec.
The velocity of car after .t. sec is
`V_(car)=at=a((2u)/(a))=2u`
The velocity of car w.r.t bike is `V_(rel)=2u-u=u`
Promotional Banner

Similar Questions

Explore conceptually related problems

A car starts from rest and moves with uniform acceleration 'a', At the same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet ? What is the velocity of car with respect to the bike at the time of meeting?

A car starts from rest and travels with uniform acceleration a, for some time and then with uniform retardation beta and comes to rest. If the total time of car is 't', the maximum velocity attained by it is given by

A car starts from rest and travels with uniform acceleration prop , for same time and then with uniform retardation beta and comes to rest. The time of motion t. Find the maximum velocity attained by it, (alphabetat//(alpha+beta))