A particle moving along a straight line with initial velocity u and acceleration a continues its motion for n seconds.What is the distance covered by it the last nth second?

Explanation

`S=ut+(1)/(2)at^(2)`
Displacement in n seconds =`un+(1)/(2)an^(2)`
Displacement in (n-1) seconds `=u(n-1)+(1)/(2)a(n-a)^(2)`
Displacement in `n^(th)` second=Displacement in n seconds
-displacement in (n-1) seconds.
`therefore S_(n)u+a(n-(1)/(2))`.