A stone is dropped from a height 300 m and at the same time another stone is projected vertically upwards with a velocity of `100m//sec`. Find when and where the two stones meet.

Explanation

Suppose the two stones meet at a height x from ground after t seconds.
`x=100t-(1)/(2)"gt"^(2)`………(1) `300-x=0+(1)/(2)"gt"^(2)`…………(2)
Solve 1,2 t=3 sec, x=255.9 m