A stone is dropped into a well and the sound of splash is heard after 5.3 sec.If the water is at a depth of 122.5 m from the ground,the velocity of sound in air is

Explanation

If `t_(1)` is time taken by some to reach the ground and `t_(2)` the time by sound to go up,the `t_(1)+t_(2)=5.33`
Since`S=ut+(1)/(2)at^(2) " "122.5=0t+(1)/(2)xx9.8xxt_(1)^(2)`
`therefore t_(1)^(2)=(245)/(9.8)=(2450)/(98)=25 " "therefore t_(1)=5s`
`therefore t_(2)`=0.33s
velocity of sound=`("displacement")/("time")=(122.5)/(0.33)=367m//s`