A stone is dropped into water from a bridge 44,1 m above the water.Another stone is thrown vertically downward 1 s later.Both strike the water simultaneously .What was the intitail speed of the second stone?

Explanation

`t=sqrt((2xx44.1)/(9.8))s=sqrt(9s)=3s`,
`44.1=vxx2+(1)/(2)xx9.8xx2xx2`
or 2v=44.1`-4.9xx4=24.5` or
`v=(24.5)/(2) ms^(-1)=12.25 ms^(-1)`