Home
Class 12
PHYSICS
A balloon starts from rest from the grou...

A balloon starts from rest from the ground and moves with uniform acceleration g/8.When it reaches a height h a ball is dropped from.It find the time taken by the ball to reach the ground.

Text Solution

Verified by Experts

Velocity of balloon when it is at a height h is
`v=sqrt((2gh)/(8))=(sqrt(gh))/(2)`
`-h=vt-(1)/(2)"gt"^(2)`
`=-h=(sqrt(gh))/(2)t-(1)/(2)"gt"^(2)`
`(1)/(2)"gt"^(2)-(sqrt(gh))/(2)t-h=0`

Simplifying and taking only the positive value as negative value of t is not acceptable
we get`t=2sqrt((h)/(g))`
Promotional Banner

Similar Questions

Explore conceptually related problems

From the top of a cliff of height 19.6m a ball is projected horizontally. Find the time taken by the ball to reach the ground (g =9.8 ms^(-2)) .

A balloon rises with uniform velocity of 10 ms^(-1) . When the balloon is at a height of 75 m if a stone is dropped from it the time taken by it to reach the ground is

A balloon starts from rest, moves vertically upwards with an acceleration g/8 "ms"^(-2) . A stone falls from the balloon after 8s from the start. Find the time taken by the stone to reach the ground (g=9.8 ms^(-2))