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A body is prijected vertically up with v...

A body is prijected vertically up with velocity u from a tower.If reaches the ground with velocity nu.The height of the tower is `H=(u^(2))/(2g)(n^(2)-1)`

Text Solution

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`v^(2)-u^(2)` 2as,Here u=u,v nu, a=-g,s=-H
`(nu)^(2)-u^(2)=2gh`
`(n^(2)-1)u^(2)=2gH" "H=(u^(2))/(2g)(n^(2)-1)`
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