In given arrangement, 10 kg and 20 kg blocks are kept at rest on two fixed inclined planes. All strings and pulleys are ideal. Value (s) of m for which system remain in equilibrium are `(g=10m//s^(2))`

In the arrangement shown, the 2 kg block is held to keep the system at rest. The string and pulley are ideal. When the 2kg block is set free, by what amount the tension in the string changes? [g=10m//s^(2)]

In the arrangement shown, the 2 kg block is held to keep the system at rest. The string and pulley are ideal. When the 2kg block is set free, by what amount the tension in the string changes? [g=10m//s^(2)]

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A block of mass 2 kg rests on an inclined plane of inclination angle 37^(@) , then calculate the force of friction acting on the block [ take g = 10 m//s^(2))

Find the acceleration of the 6 kg block in the figure. All the surfaces and pulleys are smooth. Also the strings are inextensible and light. [Take g = 10 m//s^(2) ] .

Find the acceleration of the 6 kg block in the figure. All the surfaces and pulleys are smooth. Also the strings are inextensible and light. [Take g = 10 m//s^(2) ] .

An arrangement of pulleys and blocks is shown in the figure . The two pulleys and the strings are ideal. If m_(2) gt m_(1) , then which of the following (s) is / are wrong ?

In the system of pulleys shown what should be the value of m_(1) such that 100 gm remains at rest : (Take g = 10 m//s^(2) )