The circles `2x^(2)+2y^(2)+px+6y-10=0` and `3x^(2)+3y^(2)+15x+py+21=0` are orthogonal then p=

If the two circles 2x^(2) +2y^(2) -3x+6y+k=0 and x^(2) +y^(2) -4x +10y +16=0 cut orthogonally, then the vlaue of k is-

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

If 2x^(2)+2y^(2) +4x+5y+1=0 and 3x^(2)+3y^(2)+6x -7y+3k=0 are orthogonal ,then value of k is

The value of k, if the circles 2x ^(2) + 2y ^(2) - 4x + 6y = 3 and x ^(2) + y ^(2) + kx + y =0 cut orthogonally is

The locus of the centers of the circles which cut the circles x^(2) + y^(2) + 4x – 6y + 9 = 0 and x^(2) + y^(2) – 5x + 4y – 2 = 0 orthogonally is

If the two circles 2x^(2)+2y^(2)-3x+6y+k=0 and x^(2)+y^(2)-4x+10y+16=0 cut orthogonally,then find the value of k .

The locus of the centre of the circle which cuts the circles x^(2) + y^(2) + 4x - 6y + 9 = 0 " and " x^(2) + y^(2) - 5x + 4y + 2 = 0 orthogonally is