Find the frequency of revolution of an electron in Bohr's 2nd orbit, if the radius and speed of electron in that orbit is `2.14 xx 10^(-10)m and 1.09xx10^(6)m//s` respectively.
`[pi=3.142]`

Find the frequency of revolution of an electron in Bohr's 2nd orbit; if the radius and speed of electron in that orbit is 2.14×10^(−10) m and 1.09×10^6m/s respectively.

Determine the frequency of revolution of the electron in 2nd Bohr's orbit in hydrogen atom.

The number of revolutions made by electron in Bohr's 2nd orbit of hydrogen atom is

Calculate the frequency of revolution of the electron in this second Bohr orbit of the hydrogen atom. The radius of the orbit is 2.14 Å and the speed of the electron in the orbit is 1.09 xx 10^(6) m//s .

The speed of the electron in the first orbit is 2.182 xx 10^(6) m//s , the speed of electron in the third orbit is

Calculate the frequency of revolution of the electron in the first Bohr orbit of H-atom, if the radius of the 1st Bohr orbit is 0.50 A^@ and the velocity of electron in the first orbit = 2.24 xx 10^6 m//s .

Calculate the frequency of revolution of electron in the first Bohr orbit of hydrogen atom, if radius of first Bohr orbit is 0.5Å and velocity of electron in the first orbit is 2.24xx10^6m//s .

Calculate the frequency of revolution of electron in the second Bohr's orbit of radius 2.12Å. Given, h=6.6xx10^(-34)Js, m=9xx10^(-31)kg .

The radius of orbit of an electron and the speed of electron in the ground state of hydrogen atom are 5 . 5 xx 10 ^(-11) m and 4 xx 10^(6) ms^(-1) respectivley . Then , the orbital period of this electron in the first excited state will be . . . . . .