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Important Trick For JEE Mains Students || sum_(n=0)^oo n/3^n

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sum_(n=0)^oo((2i)/(3))^n=

sum_(n=1)^(oo) (2n)/(n!)=

Find sum_(n=1)^oo (0.4)^n

Find: sum_(n=1)^oo 0.4^n

The value of sum_(n=1)^(oo)(4n-2)/(3^(n))

sum_(n = 0)^(oo) ((2i)/(3))^n =

sum_ (n = 0)^(oo) ((2i)/(3))^(n) =