" A continuously differentiable function "Phi(x)in(0,pi)" satisfying "y'=1+y^(2),y(0)=0=y(pi)" is "

A continuously differentiable function phi(x)in (0,pi//2) satisfying y'=1+y^(2),y(0)=0 , is

A continuously differentiable function phi(x)in (0,pi//2) satisfying y'=1+y^(2),y(0)=0 , is

if y(x) is satisfy the differential equation (dy)/(dx)=(tan x-y)sec^(2)x and y(0)=0. Then y=(-(pi)/(4)) is equal to

Let y=g(x) be the solution of the differential equation sin x(dy)/(dx)+y cos x=4x, x in (0,pi) If y(pi/2)=0 , then y(pi/6) is equal to

Let y=g(x) be the solution of the differential equation sinx ((dy)/(dx))+y cos x=4x, x in (0,pi) If y(pi/2)=0 , then y(pi/6) is equal to

Let y=g(x) be the solution of the differential equation (sin(dy))/(dx)+y cos x=4x,x in(0,pi) If y(pi/2)=0,theny(pi/6)^(*) is equal to

Let f(x) be a differentiable function satisfying f(y)f(x/y)=f(x) AA , x,y in R, y!=0 and f(1)!=0 , f'(1)=3 then

Let f(x) be a differentiable function satisfying f(y)f((x)/(y))=f(x)AA,x,y in R,y!=0 and f(1)!=0,f'(1)=3 then