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If `5 cos 2theta + 2 cos^2 (theta/2) + 1 = 0`,`-pi < theta < pi` , then `theta` can be

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If 5 cos 2 theta +2 cos^2 (theta/2)+1=0 , when (0 ltthetalt pi) , then the values of theta are :

Solve 5 cos 2 theta+2 "cos"^(2) theta/2 +1=0, -pi lt theta lt pi .

Knowledge Check

  • If 5 cos 2 theta + 2 cos^2" " (theta)/2 + 1 = 0, - pi lt theta lt pi , then theta =

    A
    `pi/3`
    B
    `pi/3, cos^(-1) "" (3/5)`
    C
    `cos^(-1)"" (3/5)`
    D
    `pm pi/3 , pi - cos^(-1)"" (3/5)`

  • If 5 cos 2 theta + 2 cos ^(2) ""(theta)/(2) + 1 = 0 , - pi lt theta lt pi then number of solutions are

    A
    3
    B
    4
    C
    5
    D
    6

  • If 5 cos 2 theta +2 cos^2 theta/2+1 =0, where 0 lt theta lt pi , then the values of theta are

    A
    `pi/3 +- pi`
    B
    `pi/3,cos^(-1)(3/5)`
    C
    `cos^(-1)(3/5)+- pi`
    D
    `pi/3,pi-cos^(-1)(3/5)`

    • Similar Questions

    Explore conceptually related problems

    Solve 5 cos 2 theta+2 "cos"^(2) theta/2 +1=0, -pi lt theta lt pi .

    Solve : 5cos2theta+2cos^2(theta/2)+1=0,-pi lt theta lt pi

    Solve : 5cos2theta+2cos^2(theta/2)+1=0,-pi lt theta lt pi

    Solve : 5cos2theta+2cos^2(theta/2)+1=0,-pi lt theta lt pi

    Solve the following equation (i) 5cos2theta+2cos^(2)"(theta)/(2)+1=0 , -(pi)/(2) lt theta lt (pi)/(2) (ii) sin7theta+sin4theta+sintheta=0 , 0 le theta le pi (iii) tantheta+sectheta=sqrt(3) , 0 le theta le 2pi

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