There is a uniform electric field in the XOY plane represented by `(40hat(j)+30hat(j))Vm^(-1)`. If the electric potential at the origin is 200 V, the electric potential at the point with coordinates (2m,1m) is

ABC is an equilateral triangle of side 2m. There is a uniform electric field of intensity 100V/m in the plane of the triangle and parallel to BC as shown. If the electric potential at A is 200V, then the electric potentials at B and C.

An electric field vec(E) = (25 hat(i) + 30 hat(j)) NC^(-1) exists in a region of space. If the potential at the origin is taken to be zero then the potential at x = 2m, y = 2m is :

An electric field vec(E)=(10 hat(i) + 20 hat(j)) N//C exists in the space. If the potential at the origin is taken to be zero, find the potential at (3m, 3m).

An electric field vec E=(25hat i+30hat j)NC^(-1) exists in a region of space.If the potential at the origin is taken to be zero then the potential at x =2 m y =2 m is :?

If the equation of an electric field is vec(E ) = (y hat(i) + xhat(j)) , then the equation of electric potential is represented by

Consider a uniform electric field in the hat (z) direction. The potential is a constant.

Consider a uniform electric field in the hat (z) direction. The potential is a constant.

Consider a uniform electric field in the hat (z) direction. The potential is a constant.