Prove that the internal bisector of the angle A of a triangle ABC divides BC in the ratio AB:AC

Assertion (A) : AD is angle bisector of angleA of the triangle ABC. If AB = 6 cm, BC = 7 cm, AC = 8 cm then BD = 3 cm and CD = 4 cm. Reason (R) : The angle bisector AD of the triangle divides base BC in the ratio AB : AC.

The internal angle bisector of an angle of a triangle divide the opposite side internally in the ratio of the sides containgthe angle

Internal bisector of an angle angle A of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent the sides of DABC then

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

If the bisector of the angle A of triangle ABC meets BC in D, prove that a=(b+c)[1-([AD]^(2))/(bc)]^((1)/(2))