The potential different across the Coolidge tube is `20 kV and 10 m A` current flows through the voltage supply. Only `0.5%` of the energy carried by the electrons striking the largest is converted into X-ray. The power carried by the X-ray beam is `p`. Then

The potential different across the Coolidge tube is 20 kV and 10 m A current flows through the voltage supply. Only 0.5% of the energy carried by the electrons striking the target is converted into X-ray. The power carried by the X-ray beam is p . Then find p .

The potential different across the Coolidge tube is 20 kV and 10 m A current flows through the voltage supply. Only 0.5% of the energy carried by the electrons striking the target is converted into X-ray. The power carried by the X-ray beam is p . Then

The potential difference across an X ray tube is 12.4 kV and the current through the filament is 2 mA. Calculate : (i) The number of electrons striking per second on the anode. (ii) The speed with which the electron strikes the target. (iii) The shortest wavelength of X-ray emitted.

The potential difference applied to an X - ray tube is 5 kV and the current through it is 3.2 . Then the number of electrons striking the target per second is

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electros striking the target par second is

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electros striking the target par second is

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons stricking the target per second is ...... (Take e=1.6xx10^(-19)C)