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200 g of ice at –20°C is mixed with 500 ...

200 g of ice at `–20°C` is mixed with 500 g of water `20°C` in an insulating vessel. Final mass of water in vessel is (specific heat of ice `– 0.5 cal g^(–1°)C^(–1)`)

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2kg ice at -20"^(@)C is mixed with 5kg water at 20"^(@)C . Then final amount of water in the mixture will be: [specific heat of ice =0.5 cal//gm "^(@)C , Specific heat of water =1 cal//gm"^(@)C , Latent heat of fusion of ice = 80 cal//gm]

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10g of water at 30^(@)C and 5g of ice at -20^(@) C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice= 0.5 cal g^(-1) (""^(0)C)^(-1) and latent heat of fusion of ice =80 cal g^(-1)

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