if `log[4-5log_(32)(x+3)]=0` find x

solve for x if log_(4)log_(3)log_(2)x=0 and log_(e)log_(5)(sqrt(2x+2)-3)=0

If (log_(3)x)(log_(5)3)=3 , find x.

if log_2(log_3(log_4x))=0 and log_3(log_4(log_2y))=0 and log_3(log_2(log_3z))=0 then find the sum of x, y and z is

Find x, if : (i) log_(3) x = 0 (ii) log_(x) 2 = -1 (iii) log_(9) 243 = x (iv) log_(5) (x - 7) = 1 (v) log_(4) 32 = x - 4 (vi) log_(7) (2x^(2) - 1) = 2

If log_(5) log_(5) log_(3) x = 0 , then value of x is

If log_(2)(log_(3)(log_(4)(x)))=0 and log_(3)(log_(4)(log_(2)(y)))=0 and log_(4)(log_(2)(log_(2)(z)))=0 then the sum of x,y and z is _(-)

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_2 log_3 log_4 (x+1) =0, then x is :-