In the figure shown, the heavy ball of mass `2m`, rests on the horizontal surface and the lighter ball of mass `m` is dropped from a height `h gt 2l`. At the instant the string gets taut, the upward the velocity of the heavy ball will be

In the figure shown, the heacvy ball of mass 2m rests on the horizontal surface and the lighter balls of mass m is dropped from a height hgt2l. At the instant the string gets taut, the upward velocity of the heavy ball will be :

In the shown figure, the heavu block of mass 2 kg rests on the horizontal surface and the lighter block of mass 1 kg is dropped from a height of 0.9 m . At the instant the string gets taut, find the upwards speed (in m//s ) of the heavy block.

In the shown figure, the heavu block of mass 2 kg rests on the horizontal surface and the lighter block of mass 1 kg is dropped from a height of 0.9 m . At the instant the string gets taut, find the upwards speed (in m//s ) of the heavy block.

In the shown figure, the heavu block of mass 2 kg rests on the horizontal surface and the lighter block of mass 1 kg is dropped from a height of 0.9 m . At the instant the string gets taut, find the upwards speed (in m//s ) of the heavy block.

A ball of mass m_(1) and another ball of mass m_(2) are dropped from equal height. If the time taken by the balls are t_(1) and t_(2) , respectively, then

A triangular wedge of mass M is moving with uniform velocity v_(0) along a smooth horizontal surface in the leftward direction. A particle of mass m falls from rest from height h onto the inclined face, colliding elastically with it. Find velocity of the ball and wedge after the impact taking M = 2m.

A ball of mass m_(1) , collides elastically and head on with ball of mass m_(2) at rest. Then

A ball of mass 1kg is dropped from a height of 5m. (a) Find the kinetic of the ball just before it reaches the ground (b) What is the speed at this instant?