A particle of mass `2 kg` located at the position `(hati + hatj)m` has velocity `2(hati - hatj + hatk) m//s` . Its angualr momentum about Z-axis in `kg m^(2)//s` is

A particle of mass 2 kg located at the position (hati + hatj)m has velocity 2(hati - hatj + hatk) m//s . Its angular momentum about Z-axis in kg m^(2)//s is

A particle of mass 2 kg located at the position (hat i+ hat k) m has a velocity 2(+ hat i- hat j + hat k) m//s . Its angular momentum about z- axis in kg-m^(2)//s is :

A particle of mass 2 mg located at the position (hat i+ hat k) m has a velocity 2(+ hat i- hat j + hat k) m//s . Its angular momentum about z- axis in kg-m^(2)//s is :

A particle of mass 2 kg located at the position (vec(i) + vec(j)) m has a velocity =2( vec(i) - vec(j) + vec(k)) m//s . Its angular momentum about z-axis in kg - m^(2)//s is :

A particle of mass 0.01 kg having position vector vecr = ( 10 hati + 6 hatj) meters is moving with a velocity 5 hati m/s . Calculate its angular momentum about the origin.

A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by vecr(t)=5hati-2t^(2)hatj . The angular momentum of the particle at t = 2s about the origin in kg m^(-2)s^(-1) is :

A block of mass 2 kg is moving with a velocity of 2hati-hatj+3hatk m/s. Find the magnitude and direction of momentum of the block with the x-axis.

A particle of mass 2.4kg is having a velocity of (3hati+4hatj)m/s at (5,6)m.The angular momentum of the particle about (1,2)m ,in kgm^(2)/s ,is?