A solution weighing `a` g has molality `b`. The molecular mass of solute if the mass of solute is c g, will be:

when 1.80 g of a nonvolatile solute is dissolved in 90 g of benzene, the boiling point is raised to 354.11K . If the boiling point of benzene is 353.23K and K_(b) for benzene is 2.53 KKg mol^(-1) , calculate the molecular mass of the solute. Strategy: From the boiling point of the solution, calculate the boiling point elevation, DeltaT_(b) , then solve the equation DeltaT_(b)=K_(b)m for the molality m . Molality equals moles of solute divided by kilograms of solvent (benzene). By substituting values for molality and kilograms C_(6)H_(6) , we can solve for moles of solute. The molar mass of solute equals mass of solute (1.80 g) divided by moles of solute. The molecular mass (in amu) has the same numerical value as molar mass in g mol^(-1) .

A solution of urea contains 8.6 g per litre. It is isotonic with 5% solution of a non-volatile solute. The molecular mass of the solute will be :

A solution of urea contains 8.6 g per litre. It is isotonic with 5% solution of a non-volatile solute. The molecular mass of the solute will be :

An aqueous solution containing 6 g of urea in 500 mL of solution has a density equal to 1.05. If the molar mass of urea is 60, then the molality of solution is :

An aqueous solution containing 6 g of ureas in 500 mL of solution has a density equal to 1.05. if the molar mass of urea is 60. then the molality of solution is

A solution containing 10 g per dm^(3) of urea (mol.wt. = 60 g mol^(-1) ) is isotonic with a 5% ( mass//vol.) of a non-volatile solute. The molecular mass of non-volatile solute is:

A solution containing 10 g per dm^(3) of urea (mol.wt. = 60 g mol^(-1) ) is isotonic with a 5% ( mass//vol.) of a non-volatile solute. The molecular mass of non-volatile solute is:

The density of 2.0 M solution of solute is 1.2 gm/ml. If the molecular mass of solute is 100 gm "mol"^(-1) then the molality of the solution is

The density of 2.0 M solution of a solute is 1.2 g mL^(-1) . If the molecular mass of the solute is 100 g mol^(-1) , then the molality of the solution is