A body with mass `2kg` moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest at `x=2m`, then its speed when it crosses `x=5m` is `:-`

A body with mass 1kg moves in one direction in the presence of a force which is described by the potential energy graph. If the body is releasd from rest at x=2 m , than its speed when it crosses x=5 m , is (Neglect dissipative forces).

A body with mass 1kg moves in one direction in the presence of a force which is described by the potential energy graph. If the body is releasd from rest at x=2 m , than its speed when it crosses x=5 m , is (Neglect dissipative forces).

A body of mass 2 kg is moving under the influence of a central force whose potential energy is given by U = 2r^(3) J . If the body is moving in a circular orbit of 5 m , its energy will be

Calculate the potential energy of a body of mass 5 kg at a height of 2m from the ground.

A body of mass 2kg is projected vertically upwards with a speed of 3m//s . The maximum gravitational potential energy of the body is :

A body of mass 2.4 kg is subjected to a force which varies with distance as shown in figure. The body starts from rest at x = 0. Its velocity at x = 9 m is

A body of mass 6 kg is kept at a height of 5 m from the surface of earth. Find the potential energy of the body.

A body of mass 2 kg moves with a velocity of 5 m/s. Find its kinetic energy.

A body of mass 2 kg is at rest. What should be the magnitude of force which will make the body move with a speed of 30 m/s at the end of 1 s?