Consider a circle,`x^(2)+y^(2)=1` and 'Point `P(1,sqrt(3))` .PAB is a secant drawn from P intersecting circle in A and B (distinct) then range of `|PA|+|PB|` is
(A) `[2,2sqrt(3)]" " `(B) `(2sqrt(3),4]`
(C) `(0,4] " "`(D) None of these

P is a point outside a circle and is 26cm away from its centre.A secant PAB drawn from intersects the circle at points A and B such that PB = 32 cm and PA = 18 cm. The radius of the circle ( in cm ) is :

A(1/sqrt(2), 1/sqrt(2)) is a point on the circle x^2 + y^2 = 1 and B is another point on the circle such that AB = pi/2 units. Then coordinates of B can be : (A) (1/sqrt(2), - 1/sqrt(2)) (B) (-1/sqrt(2), 1/sqrt(2)) (C) (-1/sqrt(2), - 1/sqrt(2)) (D) none of these

A line is drawn form A(-2,0) to intersect the curve y^(2)=4x at P and Q in the first quadrant such that (1)/(AP)+(1)/(AQ) sqrt(3)(B) sqrt(2)(D)>(1)/(sqrt(3))

Given b=2,c=sqrt(3),/_A=30^(0), then inradius of o+ABC is (sqrt(3)-1)/(2) (b) (sqrt(3)+1)/(2) (c) (sqrt(3)-1)/(4) (d) none of these

From point P(4,0) tangents PA and PB are drawn to the circle S:x^(2)+y^(2)=4. If point Q lies on the circle,then maximum area of /_QAB is -(1)2sqrt(3)(2)3sqrt(3)(3)4sqrt(3)A)9

Tangents PA and PB are drawn to the circle x^(2)+y^(2)=4, then locus of the point P if PAB is an equilateral triangle,is equal to

Tangents are drawn to x^(2)+y^(2)=16 from the point P(0,h). These tangents meet the x- axis at A and B. If the area of triangle PAB is minimum,then h=12sqrt(2) (b) h=6sqrt(2)h=8sqrt(2) (d) h=4sqrt(2)

A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

P is a point outside a circle with centre O, and it is 14 cm away from the centre. A secant PAB drawn from P intersects the circle at the points A and B such that PA = 10 cm and PB = 16 cm. The diameter of the Circle is: