If the variate takes the values `0,2,4,8..........2^(n)` with frequencies `^(n)C_(0),^(n)c_(1),.....^(n)c_(n)` and mean is `(91times8)/(2^(n))` then `n` is

If a variable takes value 0,1,2,3,..., n with frequencies 1,C_(1),C_(2),......C_(n)

Consider the date on x taking the values 0,2,4,8,………., 2^(n) with frequencies ""^(n)C_(0) , ""^(n)C_(1), ""^(n)C_(2),……..,""^(n)C_(n) respectively . If the mean of this data is (728)/(2^(n)) then n is equal to ________.

The mean of then Numbers 0,1,2,3.......n with respective weights ""^(n)C_(0),""^(n)C_(1),""^(n)C_(2)........""^(n)C_(n) is

If the variable takes values 0,1,2,…, n with frequencies q^(n),""^(n)C_(1)q^(n-1)p, ""^(n)C_(2)q^(n-2)p^(2), ... ""^(n)C_(n)p^(n), " where " p+q=1 , then the mean is

If .^(n)C_(8) = .^(n)C_(2) , find .^(n)C_(2) .

If ^(n)C_(8)=^(n)C_(6), then find ^(n)C_(2)