If `50!` is perfectly divisible by `75^n` ,then `n` can be

n^(3)+2n divisible by

Find the maximum value of n such that 570xx60xx30xx90xx100xx50xx700xx343xx720xx81 is perfectly divisible by 30^(n) .

5^(n)-1 is always divisible by (n in N)

n^7-n is divisible by 42 .

The 100^(th) term of the series 3+8+22+72+266+103+...... is divisible by 2^(n), then the value of n can be

If 44! is divisible by 3^(n) then maximum value of n