Consider a curve `(2x+y-1)^(2)=5(x-2y-3)` then the possible coordinates of foci are

The area enclosed by the curve y=(x-1)(x-2)(x-3) between the coordinate axes and the ordinate at x=3 is

Find the slope of the tangent to the curve y=x^(3)-3x+2 at the point whose x-coordinate is 3 .

A particle moves along the curve y = 4x^(2)+ 2 , then the point on the curve at which -y coordinates is changing 8 times as fast as the x-coordinate is

Find the slope of the tangent to curve y=x^(3)-x+1 at the point whose x-coordinate is 2 .

The coordinates of the point on the curve (x^(2)+ 1) (y-3)=x where a tangent to the curve has the greatest slope are given by

1.Find the slope of tangent to the curve y=3x^(2)-6 at the point on it whose x - coordinate is 2.

Consider the two curves C_(1);y^(2)=4x,C_(2)x^(2)+y^(2)-6x+1=0 then :