`"(cos theta+i sin theta)^(6)(cos theta-i sin theta)^(-3)`

((cos3 theta+i sin3 theta)^(5)(cos theta-i sin theta)^(3))/((cos5 theta+i sin5 theta)^(7)(cos2 theta-i sin2 theta)^(5))

((cos2 theta+i sin2 theta)^(3)(cos3 theta-i sin3 theta)^(5))/((cos3 theta+i sin3 theta)^(2)(cos4 theta+i sin4 theta)^(3))=

If theta=(pi)/(6) then the 10^(th) term of the series : 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+

if theta=(pi)/(6) then the 10 th term of the series 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^(n)=

In the form of A+iBz=(cos2 theta+i sin2 theta)^(-5)(cos3 theta-i sin3 theta)^(6)(sin theta-i cos theta)^(3) is

Express the following in a+ib form: ((cos2 theta-i sin2 theta)^(4)(cos4 theta+i sin4 theta)^(-5))/((cos3 theta+i sin3 theta)^(-2)(cos3 theta-i sin3 theta)^(-9))

(cos theta + i sin theta)^3 xx (cos theta-i sin theta)^4=

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^n=

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta