A bullet of mass 10 g moving with a speed of `20 m//s` hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if `50%` of the lost kinetic energy goes to ice?
(Temperature of ice block `= 0^@C`.)

A bullet of mass 10 g moving with a speed of 20 m/s hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if 50\% of the lost KE goes to ice? (initial temperature of the ice block and bullet = 0^(@)C )

A bullet of mass 10xx10^(-3) moving with a speed of 20ms^(-1) hits an ice block (0^(@)C) of 990g kept at rest on a frictionless floor and gets embedded in it. If ice takes 50% of K.E, the amount of ice melted (in grams) approximately is (J=4.2J/cal) (latent heat of ice=80cal/g)

A bullet of mass 10 g moving with 300m//s hits a block of ice of mass 5 kg and drops dead. The velocity of ice is

A bullet of mass 10 g moving with 300m//s hits a block of ice of mass 5 kg and drops dead. The velocity of ice is

If the mass of steam is 50g , how much ice will melt ?

A 50 g bullet moving with velocity 10 m / s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be