I. ` x = (1024)^(1//2)`
II. ` y^(2) = 1024`

Simplify (1024)^(-3//5) .

Show that C_(0) + C_(1) + C_(2) + …. + C_(10) = 1024

1 Petabyte (PB) = 1024

If A = [{:(x^(2), y^(2)), ("log"_(1024)a, -9):}],a =16^(25) " and if " A = A^(-1), " then "[{:(x^(2), y), (1, x^(2) + y):}]^(-1) = _____.

2, 1, 1, 2, 8, 32, 1024

In the expansion of (5^(1/2)+7^(1/8))^(1024), the number of integral terms is 128 b.129c.130

Sum of first 10 terms of the series, S= (7)/(2 ^(2)*5 ^(2)) + (13)/(5 ^(2)*8 ^(2)) + (19)/(8 ^(2) *11^(2))+ …… is : (a) (255)/(1024) (b) (88)/(1024) (c) (264)/(1024) (d) (85)/(1024)