`( sin 2 theta + 2 sin 4 theta + sin 6 theta )/(sin 4 theta + 2 sin 6 theta + sin 8 theta ) = `

sin 4 theta + 2 sin 8 theta + sin 12 theta = ?

sin4 theta.sin6 theta=

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

sin4theta can be written as................... A) 4 sin theta (1-2 sin ^(2) theta ) sqrt(1- sin ^(2) theta ) B) 2 sin theta cos theta sin ^(2) theta C) 4 sin theta - 6 sin ^(3) theta D) 4 sin theta + 6 sin ^(2) theta

sin 7 theta * sin theta+sin11theta * sin 3theta= A) sin 4 theta * sin 10theta B) cos 4 theta * cos 10 theta C) sin 8 theta * sin 4 theta D) cos 8 theta * cos 14 theta

Solve sin 6 theta=sin 4 theta-sin 2 theta .

Solve sin 6 theta=sin 4 theta-sin 2 theta .

Solve sin 6 theta=sin 4 theta-sin 2 theta .

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta