A simple pendulum bob has a mass `''m''` and length `''L''`. The bob is drawn aside such that the string is horizontal and then it is released. The velocity of the bob while it crosses the equilibrium position is

Mass of the bob of a pendulum is 100g and the length of the string is 1m . The bob is initially held is such a way that the string is horizontal . The bob is then released. Find the kinetic energy of the bob when the string makes an angle of (ii) 30^@ with the vertical .

Mass of the bob of a pendulum is 100g and the length of the string is 1m . The bob is initially held is such a way that the string is horizontal . The bob is then released. Find the kinetic energy of the bob when the string makes an angle of (i) 0^@ with vertical

A simple pendulum of bob mass m and length l is displaced from its mean position O to a point A and then released . If v is the velocity of the bob at O, h is the height of string of pendulum when bob passes through point O is /are (neglect friction )

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60^(@) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

The length of a simple pendulum of 0.4 m. The bob of the pendulum is drawn aside till the string is horizontal, it is then released from this horizontal position, What will be its velocity when it reached the lowest point in its swing ? (g = 9.8 m//s^(2)) [Hint : Loss in potential energy = gain in kinetic energy]

Effective length of a pendulum is 50 cm and the mass of the bob is 4g . The bob is drawn to one side until the string is horizontal , and is then released. When the string makes an angle 60^@ with the vertical , what is the velocity and the kinetic energy of the bob ?

the velocity of the bob of a simple pendulum is minimum at _____