One end of a diameter of the circle `x^(2) + y^(2) = 2 ` is (1,-1) . Then coordinates of its other end is

If the coordinates of one end of a diameter of the circle x^(2) + y^(2) + 4x-8y + 5=0 is (2,1), the coordinates of ihe other end is

If the coordinates of one end of a diameter of the circles x^(2)+y^(2)+4x-8y+5=0 is (2,1),, the coordinates of the other end is

If the coordinates at one end of a diameter of the circle x^(2) + y^(2) - 8x -4y + c=0 are (11,2) the coordinates of the other end are

If the coordinates of one end of a diameter of the circle x^2+y^2+4x-8y+5=0 , is (2, 1), the coordinates of the other end is

If the coordinate of one end of a diameter of the circle x^2+y^2+4x−8y+5=0 is (2,1), the coordinates of the other end is a) (-6,--7) b) (6,7) c) (-6,7) d) (7,-6)

One end of a diameter of the circle x^2+y^2-3x+5y-4=0 is (2,1). Find the coordinates of the other end.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.