ABC be a triangle with `A(1,3), y = x, y = -2x` are the equations of internal angular bisectors of `/_B and /_C` and area of triangle ABC is k units, then `2k` is

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

In a triangle ABC.if A(1,2) and the internal angle bisetors through B and C are y=x and y=-2x, then the in radius r of Delta ABC is :

In a triangle ABC, if A-=(1,2) and the internal angle bisectors through B and C are y=x and y=-2x, then the inradius r of DeltaABC is

In a Delta ABC, points A and B are (4, 5) and (h, k) respectively. If the equation to the angle bisector of B is y=x and the orthocentre of the triangle is (3,3) then the value of [h+k], where [.] denotes the greatest integer function, is

In a triangle ABC,A(1,3) and perpendicular bisector of AB is y=x and orthocentre of triangle ABC is (3,1), then locus of vertex C is