Two mutually perpendicular simple harmonic vibrations have same amplitude, frequency and phase. When they superimpose, the resultant form of vibration will be

When two mutually perpendicular simple harmonic motions of same frequency, amplitude and phase are superimposed.

When two mutually perpendicular simple harmonic motions of same frequency, amplitude and phase are susperimposed

In a simple harmonic mode of vibration, on a string

Find the phase different between two particles executing simple harmonic motion with the same amplitude and frequency when their phases at a certain moment are as shown in the figure.

Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along X-axis and Y-axis. If the two amplitudes are equal and the phase difference is pi//2 , the resultant motion will be

Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along X-axis and Y-axis. If the two amplitudes are equal and the phase difference is pi//2 , the resultant motion will be

Two simple harmonic oscillations of the same frequency and amplitude and a phase difference of pi/2 , superimpose on each other at difference of right angles to each other. The resultant motion will be

Two simple harmonic motions with the same frequency act on a particle at right angles i.e, along x and y axis. If the two amplitudes are equal and the phase difference is (pi)/(2) the resultant motion will be :