If `tan theta = 40/9`, then `sec theta and cos theta`.

If cot theta + tan theta = x and sec theta - cos theta = y then

Prove that: (sec theta + tan theta -1)/(tan theta - sec theta +1) = (cos theta)/(1- sin theta)

If tan theta + sec theta = n, then sec ^(4) theta - tan ^(4) theta- 2 sec theta tan theta =

(cos theta )/( sec theta + tan theta ) + ( cos theta )/( sec theta - tan theta ) =

Prove that (sec theta+tan theta -1)/(tan theta -sec theta +1)=cos theta/(1-sin theta)

If sec theta-tan theta=3 , then cos theta is equal to: यदि sec theta-tan theta=3 , है, तो cos theta बराबर है:

If tan theta + sec theta =4 , the value of sin theta cos theta .

Prove that (sin theta + cos theta )( cosec theta - sec theta ) = cosec theta. Sec theta -2 tan theta