Find the result of mixing `1kg` of ice at `0^(@)C` with `1.5kg` of water at `45^(@)C`. (Specific latent heat of fusioin of ice `=336xx10^(3)Jkg^(-1)`)

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then

What will be the result of mixing 2kg of cooper at 100^(@)C with 0.75 kg of ice at 0^(@)C (Specific heat capacity of cooper =378J kg^(-1)K^(-1) specific heat capacity of water =4200 J kg^(-1)K^(-1) and specific latent heat of fusion of ice =336xx10^(3)Jkg^(-1) )

40 g of ice at 0^(@)C is used to bring down the temperature of a certain mass of water at 60^(@)C to 10^(@)С . Find the mass of water used. [Specific heat capacity of water = 4200 Jkg^(-1)""^(@)C^(-1) ] [Specific latent heat of fusion of ice = 336xx10^(3)Jkg^(-1) ]

250 g of water at 30^(@)C is present in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5^(@)C . Specific latent heat of fusion of ice = 336xx10^(3)Jkg^(-1) Specific heat capacity of copper vessel = 400Jkg^(-1)""^(@)C^(-1) Specific heat capacity of water = 4200Jkg^(-1)""^(@)C^(-1) .

What would be the final temperature of the mixture when 1kg of ice at -10^(@)C is mixed with 4.4kg of water of 30^(@)C ? (Specific heat capacity of ice =2100Jkg^(-1)K^(-1))

A carnot refrigerator absorbs heat from water at 0^(@)C and gives it to a room at 27^(@)C. Find the work done by the refrigerator and the coefficient of performance of the machine when it changes 2 kg of water at 0^(@)C to ice at 0^(@)C. Specific latent heat of ice =333 xx 10^(3) Jkg ^(-1)?

Find the result of mixing 0.5 kg ice at 0^@C with 2 kg water at 30^@C . Given that latent heat of ice is L=3.36xx10^5 J//kg and specific heat of water is 4200 J//kg//K .