Theorem 10.5 : There is one and only one circle passing through three given non-collinear points.

There is one and only one circle passing through three non-collinear points.

There is one and only circle passing through three non-collinear points.

There is one and only circle passing through three non-collinear points.

Theorem:- 3 There is one and only one circle passing through three non collinear points and If two circles intersects in two points; then the line joining the centres is perpendicular bisector of common chords

Only one circle can be drawn through three non-colinear points.

Statement 1: The differential equation of all circles in a plane must be of order 3. Statement 2: There is only one circle passing through three non-collinear points.

Statement 1 : The differential equation of all circles in a plane must be of order 3. Statement 2 : There is only one circle passing through three non-collinear points.

Statement 1 : The differential equation of all circles in a plane must be of order 3. Statement 2 : There is only one circle passing through three non-collinear points.

Statement 1 : The differential equation of all circles in a plane must be of order 3. Statement 2 : There is only one circle passing through three non-collinear points.