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` { i^( 17 ) - ( ( 1 ) /( i ) ) ^ ( 34 ) }^ 2 `

[i^(17)-((1)/(i))^(34)]^(2)=2i .

If {i^(17)-((1)/(i))^(34)}^(2) = a + 2i , then the value of a is

Evaluate [ i^(14) - (1/i)^(34)]^2

Evaluate [ i^(14) - (1/i)^(34)]^2

Show that : (i) {i^(19) + (1/i)^(25)}^(2) = -4 " "(ii) {i^(17) - (1/i)^(34)}^(2) = 2i (iii) {i^(18) + (1/i)^(24)}^(3) = 0 " " (iv) i^n + i^(n+1) + i^(n +2) + i^(n + 3) = 0 , for all n in N .

Prove that : {i^17-(1/i)^34}^2= 2i .

[i^(17)+1/(i^(315))]^(9) is equal to

[i^(17)+1/(i^(315))]^(9) is equal to

For x in R, x ne -1 , if (1 + x)^(2016) = sum_(i = 0)^(2016) a_(i)x^(i) , then a_(17) is equal to :

sqrt((-17)/(144)-i)=