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At time t= 0, a particle is at (2m, 4m)....

At time `t= 0,` a particle is at `(2m, 4m).` It starts moving towards positive x-axis with constant acceleration `2 m//s^2` (initial velocity=0). After 2 s, an additional acceleration of `4 m//s^2` starts acting on the particle in negative y-direction also. Find after next 2 s.
(a) velocity and
(b) coordinates of particle.

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