यदि रेखा `(3x-y+5)+lambda (2x-3y-4)=0` Y अक्ष के समांतर है तो `lambda =`

If the straight line (2x + 3y +4) +lambda (6x -y + 12) = 0 is parallel to y-axis then lambda=

The line (5x-8y+11)lambda+(8x-3y+4)=0 is parallel to x -axis,then value of lambda is

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R)( a) x^(2)+y^(2)-3x-4y-4=0 (b) 2x^(2)+3y^(2)+2x+4y-7=0(c)x^(2)+y^(2)-2x-4y+4=0(d) none of these

The equations lambda x -y = 2 ,2 x -3 y = - lambda and 3x - 2y = - 1 are consistent for a) lambda=-4 b) lambda=1,4 c) lambda=1,-4 d) lambda=-1,4

If the angle between the circles x^(2) +y^(2) +4x - 5 = 0 and x^(2) +y^(2) +2lambda y- 4 = 0 "is" (pi)/(3), " then " lambda =

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0