The direction ratios of the line parallel to the line `(x-1)/(3)=(y-5)/(1)=(z-3)/(0)` are proportional to -

The direction cosines of a line parallel to the line (x+1)/(2)=(y)/(-3)=(z-5)/(6) are

Find the direction cosine of a line parallel to the line (2x-5)/(4)=(y+4)/(3)=(6-z)/(6)

Find the vector equation of the line parallel to the line : (x -1)/(5) = (3 -y)/(2) = (z + 1)/(4)

Find the directions ratios of the line perpendicular to the lines (x-7)/(2) = ( y+ 7)/(-3) =(z-6)/(1) and (x+5)/(1) = (y+3)/(2)= (z-6)/(-2)

Direction ratios of the line perpendicular to the lines (x-3)/(2) = (y+7)/( -3) = (z-2)/(1) and (x+2)/(1) = (y+3)/( 2) = ( z-5)/(-2) are

The direction ratios of the line x-y+z-5=0=x-3y-6 are

The direction ratios of the line x-y+z-5=0=x-3y-6 are

The direction ratios of the line x-y+z-5=0=x-3y-6 are

Find the equation of a line parallel to the line (x-5)/(3) = (y+1)/(-2) = (z)/(1) and passes through the point (0,-1,2) .

Find the equation of a line parallel to the line (x-5)/(3) = (y+1)/(-2) = (z)/(1) and passes through the point (0,-1,2) .