If the system of linear equations `x+ky+3z=0, 3x+ky-2z=0, 2x+4y-3z=0` has a non-zero solution `(x,y,z)` then `(xz)/(y^2)` is equal to

If the system of linear equations x+ky+3z=03x+ky-2z=02x+4y-3z=0 has a non-zero solution (x,y,z) then (xz)/(y^(2)) is equal to

The system of equations x+ky+3z=0, 3x+ky-2z=0, 2x+3y-4z=0 has a non trivial solution when k=

The system of equations: x+ky+3z=0 , 3x+ky-2z=0 , 2x+3y-4z=0 has non- trivial solution. when k=

x+ky-z=0 , 3x-ky-z=0 and x-3y+z=0 has non-zero solution for k=

x+ky-z=0 , 3x-ky-z=0 and x-3y+z=0 has non-zero solution for k=

If the system of equation x+ky+3z=0,3x+ky-2z=0,2x+3y-4z=0 has non trivial solution, then (xy)/(z^2) =

If the system of equations, 2x + 3y-z = 0, x + ky -2z = 0 " and " 2x-y+z = 0 has a non-trivial solution (x, y, z), then (x)/(y) + (y)/(z) + (z)/(x) + k is equal to

If the system of equations, 2x + 3y-z = 0, x + ky -2z = 0 " and " 2x-y+z = 0 has a non-trivial solution (x, y, z), then (x)/(y) + (y)/(z) + (z)/(x) + k is equal to