If the de-Broglie wavelength is `lambda_(0)` for protons accelerated through 100 V, then the de-Broglie wavelength for alpha particles accelerated through the same voltage will be

A proton is accelerated through 225 V . Its de Broglie wavelength is

A proton is accelerated through 225 V . Its de Broglie wavelength is

A proton is accelerated through 225 V . Its de Broglie wavelength is

A deutron is accelerated through 100 V, its de Broglie wavelength is

If lamda_(0) is the De-Broglie wavelength for a proton accelerated through a potential difference of 100 V, De- Broglie wavelength for prop- particle accelerated through the same potential difference is

What is the de - Broglie wavelength of the alpha - particle accelerated through a potential difference V ?

For a proton accelerated through V volts , de Broglie wavelength is given as lambda =

For a proton accelerated through V volts , de Broglie wavelength is given as lambda =

The De broglie wavelength associated with protons accelerated through V volt will be :