In a Young's double slit experiment the intensity at a point where tha path difference is `(lamda)/(6)` (`lamda` being the wavelength of light used) is I. If `I_0` denotes the maximum intensity, `(I)/(I_0)` is equal to

In Young's double slit experiment,the intensity at a point where the path difference is

In a Young's double slit experiment the intensity at a point where the path difference is (lambda)/(6)(lambda being the wavelength of the light used) is I. If I_(0) denotes the maximum intensity then (I)/(I_(0))=…

In a Young's double slit experiment,the intensity at a point,where the path difference is lambda//6 ( lambda being the wabelength of the light used) is I .If I_0 denotwes the maximum intensity,then I//I_0 is equal to

In Young's double slit experiment, the intensity at a point where the path difference is lamda/6 ( lamda is the wavelength of light) is I. if I_(0) denotes the maximum intensities, then I//I_(0) is equal to

In a Young's double slit experiment, the intensity at a point where the path difference is (lamda)/6 ( lamda - wavelength of the light) is 1. If I_(0) denotes the maximum intensity, then I/(I_(0)) is equal to

In young double slit experiment, the intensity at a point where path difference is lamda/6 is l. IF l_0 denotes the maximum intensity l/l_0 .

In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is lambda is K, ( lambda being the wavelength of light used). The intensity at a point where the path difference is lambda//4 will be