Home
Class 12
PHYSICS
The electric field componets due to a c...

The electric field componets due to a charge inside the cube of side 0.1m are `E_(x) = alpha x,` where `alpha = 500 (N//C) m^(-1)`,
`E_(y) = 0, E_(z) = 0`. Calculate the flux through the cube and the charge inside the cube.

Promotional Banner

Similar Questions

Explore conceptually related problems

(a) Define electric flux. Write its SI units. (b) The electric field components due to a charge inside the cube of side 0.1 m are as shown : E_(x)=alpha x, where alpha=500N//C-m E_(y)=0, E_(z)=0 . Calculate (i) the flux through the cube, and (ii) the charge inside the cube.

(a) Define electric flux. Write its SI units. (b) The electric field components due to a charge inside the cube of side 0.1 m are as shown : E_(x)=alpha x, where alpha=500N//C-m E_(y)=0, E_(z)=0 . Calculate (i) the flux through the cube, and (ii) the charge inside the cube.

(a) Define electric flux. Write its SI units. (b) The electric field components due to a charge inside the cube of side 0.1 m are as shown : E_(x)=alpha x, where alpha=500N//C-m E_(y)=0, E_(z)=0 . Calculate (i) the flux through the cube, and (ii) the charge inside the cube.

The electric field components due to a charge inside the cube of side 0.1m are as shown below: E_(x)= ax where alpha= 500N//C-m, E_(Y)= 0, E_(Z)= 0 Calculate (a) the flux through the cube and (b) the charge inside the cube.

The electric field components due to a charge inside the cube of side 0.1 m are as shown in the figure. E_X = ax, where a = 500 NC^-1m^-1E_y = 0 and E_z = 0 Calcualte the electric flux through the cube

The electric field components due to a charge inside the cube of side 0.1 m are as shown in the figure. E_X = ax, where a = 500 NC^-1m^-1E = 0 and E_2 = 0 Calcualte the charge inside the cube.

Using Gauss’s law, derive expression for intensity of electric field at any point near the infinitely long straight uniformly charged wire. The electric field components in the following figure are E_(x) = alphax, E_(y) = 0, E_(z) = 0, " in which " alpha = 400 N//C m. Calculate (i) the electric flux through the cube, and (ii) the charge within the cube assume that a = 0.1m.