If `f(x)=-1+|x-1|;-1 <= x <= 3 g(x)=2-|x+1|;-2 <= x <= 2` Find `(fog)x and (gof)x.`

Let f(x) and g(x) be two functions given by f(x)=-1|x-1|,-1 le x le 3 and g(x)=2-|x+1|,-2 le x le 2 Then,

Let f(x) and g(x) be two functions given by f(x)=-1|x-1|,-1 le x le 3 and g(x)=2-|x+1|,-2 le x le 2 Then,

If f(x)=(|x-1|)/(x-1),x!=1 and f(1)=1 then the correct statement is discontinuous at x=1

If f(x) = (x+1)/(x-1) , x != 1 then find (fofof)(x) .

If f(x) = (x-1)/(x+1) , then f[1/f(x)] =

If f(x)=(x-1)/(x+1);x!=-1 , then f^(-1)(x) is:

If f(x)= (1)/(x+1) - log (1+x), x gt 0 then f(x) is-