Calculate the voltage needed to balance on all drop carrying 10 electrons when located between the plates of a capacitor which are 5 mm apart. Mass of oil drop is `3xx10^(-16) kg `(take `g = 10m//s^(2))`

Calculate the voltage needed to balance on oil drop carrying 10 electron, when located between the plates of capacitor, which are 5 mm apart.Given, mass of drop = 3xx10^(-16)kg , charge on electron= 1.6xx10^(-19)C and g = 9.8 m/s^2 .

Calculate the voltage needed to balance an oil drop carrying 10 electrons, when located between plates of a capacitor, which are 5 mm apart. Given, mass of the drop = 3xx 10^-16 kg , charge on electrno = 1.6 xx 10^-19 C and g = 9.8 m s^-2

Calculate the voltage required to balanced an oil drop carrying 10 electrons, when located between plates of a capacitor, which are 5mm apart. Given mass of drop = 3xx10^(-16) kg , charge on electron = 1.6xx10^(-19)C and g = 9.8 m//s^(2) .

Find the magnitude of electron field which just balances a deuteron of mass 3.2 xx 10^-27 kg . (Take g = 10 ms^-2).

An oil drop with charge 1.6xx10^(-18)C is balanced in air between two metallic plates 10 mm apart. Calculate the voltage required between the plates if mass of the drop is 2.4xx10^(-14)kg .

A charged oil drop of mass 2.5xx10^(-7) kg is in space between the two plates, each of area 2xx10^(-2) m^(2) of a parallel plate capacitor. When the upper plate has a charge of 5 xx10^(-7) C and the lower plate has an equal negative charge, then the oil remains stationary. the charge of the oil drop is (take, g=10 m//s^(2) )

A charged oil drop of mass 2.5xx10^(-7) kg is in space between the two plates, each of area 2xx10^(-2) m^(2) of a parallel plate capacitor. When the upper plate has a charge of 5 xx10^(-7) C and the lower plate has an equal negative charge, then the oil remains stationary. the charge of the oil drop is (take, g=10 m//s^(2) )